Question 964666
Per Pythagoras:
{{{h= sqrt(a^2+b^2)}}} Let's square both sides to get rid of the root:
{{{h^2= a^2+b^2}}} We know one leg, let's say it's a. So:
{{{h^2-a^2=b^2}}} Substitute with numbers:
{{{7.2^2-6.4^2= b^2}}}
{{{51.84-40.96= b^2}}}Subtract on left, they take the square on both sides, and you get:
b= 3.30