Question 964576
A tennis ball is launched upward at 32 feet per second from a platform that is 15 feet tall.
Find the maximum height the ball reaches using the equation that describes the height of the tennis ball, based on time, initial velocity, and initial height.
h(t)=-16t^2+96t+200
complete the square:
h(t)=-16(t^2-6t+9)+144+200
h(t)=-16(t-3)^2+344
The ball reaches the maximum height of 344 ft 3 seconds after it is launched