Question 964458
f(x) = x^4 +23x^2 +22
first write down the factors of 22, they are
1, 22
2, 11
now 1 and 22 look promising since the coefficient of x^2 is 23
let's try
(x^2 +1) * (x^2 +22) = x^4 +23x^2 + 22
we can now write the solutions for x as
x^2 = -1
x = sqrt(-1) = i
x^2 = -22
x = sqrt(-22) = i*sqrt(22)
therefore our 2 solutions for x are
x = i and x = i*sqrt(22)