Question 82248
For example, the problem x=y^2-10y+30.  I got the vertex (5,5) and since a=1 I know it opens to the right.  I know for any constant d, the points on the parabola with y-coordinates 5-d and 5+d have the same x-coordinate.  So I plug in 1 and have the y coordinates as (  ,4) and (  ,6).  My problem is, I can't find the constant x-coordinate.  I don't know how to get the x-coordinate.  Can someone please help me figure out how to find the x-coordinate in this problem. 
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You have the y-coordinate of two points.
If y=4, x=4^2-10*4+30; x=46-40=6
If y=6, x=6^2-10*6+30; x=66-60=6
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For both of yur points the x-value is 6.
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Cheers,
Stan H.