Question 964256
The length of a rectangle is 8 inches more than its width. If 4 inches are taken from the length and added to the width, the figure becomes a square with an area of 121 square inches. What are the dimensions of the original figure?
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let x=width of original rectangle
x+8=length of original rectangle
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(x+8-4)(x+4)=121
(x+4)^2=121
x+4=√121=11
x=11-4=7
What are the dimensions of the original figure?
width=7 inches
length=x+8=15 inches