Question 964252

{{{(x-3)^2/4 + y^2/9 = 1}}}

the length of the horizontal axis is what is underneath the {{{x ^2}}} term and it is equal to {{{a}}}
 {{{a^2= 4}}}
{{{a = 2}}}



the vertical axis is what is underneath the {{{y ^2}}} term and it is equal to {{{b}}}
{{{b^2= 9}}}
{{{b = 3}}}


since the vertical axis is the longer of the two, it is the major axis 
the axis parallel to the y axis in this case is the longer of the two and is the major axis 


{{{ graph( 600, 600, -10, 10, -10, 10,sqrt((-(x-3)^2/4+1)9),-sqrt((-(x-3)^2/4+1)9)) }}}