Question 82193
f(x)=-x^3+3x^2-x+4, 
find f(-2) evaluate that equation at -2, so substitute -2 whenever you see x
so 
{{{f(-2)=-(-2)^3+3(-2)^2-(-2)+4=-(-8)+3(4)+2+4=8+12+6=26}}}
{{{f(0)=-0+0-0+4=4}}}
{{{f(3)=-(3)^3+3(3)^2-(3)+4=-27+27+1=1}}}