Question 964085
s=original side
{{{(s+6)^2=25s^2}}}
{{{s^2+12s+36=25s^2}}} Subtract 25s^2 from each side.
{{{-24s^2+12S+36=0}}} Divide each side by -12.
{{{2s^2-s-3=0}}}*[invoke quadratic "s", 2, -1, -3 ]
So s=1.5 inches.
ANSWER: The sides of the original square were 1.5 inches.
CHECK:
Original area={{{(1.5in)^2=2.25in^2}}}
{{{(1.5in+6in)^2=25(2.25in^2)}}}
{{{(7.5in)^2=56.25in^2}}}
{{{56.25in^2=56.25in^2}}}