Question 964018
2^(x^2-x+10)=16^(7-x)

Taking log with base 2 on both sides

(x^2-x+10)x log2(2)= (7-x)x log2(2^4)

=(x^2-x+10)x log(2)=(7-x)x 4xlog2(2)

cancel log2(2)on both sides

(x^2-x+10)=4(7-x)

x^2+3x-18=0

(x+6)(x-3)=0

therefore,

x=-6,3