Question 964005
{{{8^(2x+9)=1234+17}}}
{{{8^(2x+9)=1251}}}
{{{log(10,(8^(2x+9)))=log(10,1251)}}}
{{{(2x+9)log(10,8)=log(10,1251)}}}
{{{2x+9=log(10,1251)/log(10,8)}}}
{{{2x=-9+log(10,1251)/log(10,8)}}}
{{{highlight(x=-9/2+log(10,1251)/(2(log(10,8))))}}}


Compute as you like.
Maybe use {{{x=log(10,1251)/(log(10,64))-9/2}}}.

{{{x=-2.7852}}}, decimal approximation.