Question 963978
Simplify the following:
{{{(w^3/w^2)y^3}}}
Group the factors (the numbers being multiplied):
= {{{(w^3*y^3)/w^2}}}
Combine powers:
= {{{ w^(3-2)y^3}}}
Subtract 3-2 which leaves you with 1w or simply w:
= {{{w*y^3}}} This is your answer