Question 963661

{{{x^2+y^2-6x-4y+9=0}}}

{{{(x^2-6x)+(y^2-4y)=-9}}}............complete squares

{{{(x^2-6x+_)-_+(y^2-4y+_)-_=-9}}}

{{{(x^2-6x+3^2)-3^2+(y^2-4y+2^2)-2^2=-9}}}

{{{(x-3)^2-9+(y-2)^2-4=-9}}}

{{{(x-3)^2+(y-2)^2=-9+9+4}}}

{{{(x-3)^2+(y-2)^2=4}}}

so, here you have a circle with a center at ({{{3}}},{{{2}}}), diameter {{{d=4}}}, and radius {{{r=2}}}


{{{drawing( 600, 600, -10, 10, -10, 10,
circle(3,2,.12),locate(3,2,C(3,2)),circle(3,2,2),
 graph( 600, 600, -10, 10, -10, 10, 0)) }}}