Question 963651
When multiplying exponents with the same base, you add the exponents:
{{{(x^a)(x^b)=x^(a+b)}}} so:
{{{(3^(-2))(3^(-1))=3^(-2+-1)=3^(-3)}}}={{{1/(3^3)=1/27}}}
CHECK:
{{{(3^-2)(3^-1)=(1/3^2)(1/3^1)}}}={{{(1/9)(1/3)=1/27}}}