Question 963573
sin2x=cosx
----------------
2sin(x)*cos(x) = cos(x)
2sin*cos - cos = 0
cos*(2sin - 1) = 0
cos(x) = 0
x = -pi/2, +pi/2, 3pi/2
----------------
2sin - 1 = 0
sin(x) = 1/2
x = pi/6, 5pi/6