Question 963527
No, equations of the form
{{{ln(x)=y}}}
always have a solution as long as x is a valid input (i.e. x > 0). This is because logarithms have a range that extends from negative to positive infinity.

But consider this:
{{{ln(x+1)-ln(x+5)=0}}}
The equation has no solution as it would imply that
{{{ln(x+1)=ln(x+5)}}}
if it was true, which is obviously not the case.
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