Question 963414
Let the width be x.
Then the length is (x+200)
The area of the field=57600
Area=length*width
x(x+200)=57600
x^2+200x-57600=0
*[invoke quadratic "x", 1, 200, -57600 ]
x=160 or x=-360
The width of the field is 160 feet.