Question 963378
If the car goes uniformly from 0 to 60 mph in 6 seconds,
acceleration is 60mph/6s=10 miles/hr/sec
Let's change acceleration rate to feet/second/second to get uniform units:
(10mi/hr/sec)(5280ft/mi)(1 hr/3600 sec)=14.7ft/sec/sec
Let s=distance, a=acceleration, t=time
{{{s=(1/2)at^2}}}
{{{s=(1/2)(14.7ft/s^2)(6^2s^2)}}}
{{{s=(7.35ft/s^2)(36s^2)}}}=264.6 feet
Tire size does not matter unless it is used to determine speed or 
acceleration: what matters in determining distance is rate of forward motion
and rate of change of forward motion.