Question 82150
If we're given y=2f(x-6), this tells us is to shift the original graph f(x)  6 units to the right and double every output. So we're essentially starting at x=4 (the x-coordinate of our point), shifting 6 units to the right (adding 6 to 4), and then doubling the output. So our new x-coordinate is x=10. We can easily verify this by sticking x=10 into f(x-6) to get:

f(10-6)=f(4)


which is our original point. To get our new y coordinate, we simply double the output (ie our old y-coordinate y=-5). So the corresponding point on y=2f(x-6) is 

(10,-10) which is answer d)


If this is hard to grasp, make a function that goes through (4,-5) (for instance {{{y=(-5/4)x}}}) and shift the function. So y=2f(x-6) would be 

y=2f(x-6)-> {{{y=2(-5/4)(x-6)}}}


and if we plug in x=10 (remember we've shifted 6 units to the right) we get y=-10, which verifies our answer.