Question 963017
Graphing,
{{{graph(300,300,-4,4,-2,18,4^x,8x)}}}
There are two solutions near x=0 and near x=2.
You can verify that {{{x=2}}} is a solution since,
{{{4^2=8(2)}}}
{{{16=16}}}
I used Newton's method to solve for both one with a starting value of x=0.5 and one with a starting value of x=2.5.
The other value is approximately {{{x=0.15}}}
*[illustration NEWT.JPG].