Question 82094
<pre><b>
write the first four terms in the expansion of (x+3y)^8

1st term = {{{C(8,0)(x)^8(3y)^0}}}={{{(1)x^8*(1) = x^8}}}
2nd term = {{{C(8,1)(x)^7(3y)^1}}}={{{(8)x^7*3y = 24x^7y}}}
3rd term = {{{C(8,2)(x)^6(3y)^2}}}={{{((8*7)/(2*1))(x^6)3^2*y^2 = 252x^6y^2}}}
4th term = {{{C(8,3)(x)^5(3y)^3}}}={{{((8*7*6)/(3*2*1))(x^5)3^3*y^3 = 1512x^5y^3}}}
5th term = {{{C(8,4)(x)^4(3y)^4}}}
6th term = {{{C(8,5)(x)^3(3y)^5}}}
7th term = {{{C(8,6)(x)^2(3y)^6}}}
8th term = {{{C(8,7)(x)^1(3y)^7}}}
9th term = {{{C(8,8)(x)^0(3y)^8}}}

Edwin</pre>