<PRE><B>Question 962978</B>
A person invested $4100, part of it in bank bonds bearing 3.10% interest and the remainder in Canada Savings Bonds bearing 4.85% interest and she received the same income from each. 
How much, to the nearest dollar, was invested in each?
Do not round intermediate results. Round only final answers. Round to the nearest integer.
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Equation:
Interest = Interest
0.031*x = 0.0485(4100-x)
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Multiply thru by 10^4 to get:
310x = 485*4100-485x
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795x = 485*4100
x = $2501.26 (amt invested at  3.1%
4100-x = $1598.74 (amt invested at 4.85)
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Cheers,
Stan H.
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