Question 962938
for 2|3x-16| x=4 , either
2(3x-16)* x=4 or
2( -(3x-16) ) *x = 4
Take 2(3x-16)* x=4 first
(6x - 32)*x = 4
6x^2 -32x = 4
subtract 4 from each side
6x^2 -32x - 4 = 0
Using a solver we get x = {{{(1/3)(8 - sqrt(70))}}} or x = {{{(1/3)(8 + sqrt(70))}}}
Now solve 2( -(3x-16) ) *x = 4
(-6x + 32 )*x = 4
-6x^2 +32x = 4
-6x^2 + 32x -4 = 0
Multiply by -1
 6x^2 -32x + 4 = 0
solving we get x = {{{(1/3)(8 - sqrt(58))}}} or x = {{{(1/3)(8 + sqrt(58))}}}