Question 962777
{{{y=x^3 -7/(x^2-4X-5)}}}


Let y=0.


{{{0=x^3 -7/(x^2-4X-5)}}}


{{{x^3(x^2-4X-5)/(x^2-4X-5)-7/(x^2-4X-5)=0}}}


Concentrate on the NUMERATOR being zero.


{{{x^3(x^2-4x-5)-7=0}}}


{{{x^5-4x^4-5x^3-7=0}}}


Use Rational Roots Theorem, or if necessary, graphing software to find roots.
Use of Google shows one real root at very very near to 5.002.