Question 962755
Just minimize the function. Calculating f'(x), we get
{{{d/(dx)*f(x)=2x-60}}}
since
{{{f(x)=x^2-60x}}}
Setting it to 0, we get
{{{2x-60=0}}}
{{{2x=60}}}
{{{x=30}}}
You can do the first derivative test to make sure it is actually a minimum point. If x = 30, then
x - 60 = -30
and thus the two numbers are 30, -30.
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