Question 962570
{{{( 2-3i)/(1+2i)}}}
multiply by the conjugate of the denominator over itself
{{{( 2-3i)/(1+2i)}}} * {{{(1-2i)/(1-2i)}}} = {{{((2-3i)(1-2i))/((1+2i)(1-2i))}}} = {{{((2-4i-3i+6i^2))/((1+2i-2i-4i^2))}}} = {{{((2-7i+6(-1)))/((1-4(-1)))}}} = {{{((2-7i-6))/((1+4))}}} = {{{((-4-7i))/5}}}