Question 962512
Bob hits a cricket ball into air. The height (in feet) of the ball at time tseconds is given by h(t)=-10.5t^2+66.3t + 6. Find the maximum height the ball reaches and the time in seconds when that maximum height occurs
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h(t)=-10.5t^2+66.3t + 6
complete the square:
h(t)=-10.5(t^2-(66.3/10.5)t+(66.3/21)^2)+104.66 + 6
h(t)=-10.5(t-(66.3/21)^2+110.66
The ball reaches the maximum height of 110.7 ft at 3.15 sec