Question 962496


if you have {{{20=3x-4x-12}}}, then

{{{0=3x-4x-12-20}}}

{{{0=3x-4x-32}}}

{{{0=(3-4)x-32}}}

{{{0=-x-32}}}

{{{0+x=-x+x-32}}}

{{{x=-32}}}

{{{x=sqrt(-32)}}}.......{{{-32=-1(4^2*2)}}}, then

{{{x=sqrt(-1(4^2*2))}}}

{{{x=4*i*sqrt(2)}}} or {{{x=-4*i*sqrt(2)}}}