Question 962437
By the Conjugate Roots Theorem, if f(x) has real coefficients and has a complex root, then the conjugate of that complex root is also a root of f(x). Thus we immediately get

{{{f(x)=(x+4)(x-(1-i))(x-(1+i))}}}
{{{f(x)=(x+4)(x-1+i)(x-1-i)}}}