Question 962423
f(x)= (x-3) (x+2)
f(x) = x^2-x-6
a = 1
b = -1
c = -6
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Find:
 Axis of symmetry: x = -b/(2a) = 1/2
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 Vertex: (-b/2a ; f(-b/2a)) = (1/2 , (1/4)-(1/2)-6) = (1/2,-25/4)
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 Y-intercept:: f(0) = -6
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Max or Min: Min value = f(1/2) = -25/4
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Graph::
{{{graph(400,400,-10,10,-10,10,x^2-x-6)}}}
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Cheers,
Stan H.
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