Question 962408
Can tyou help please with the equation: calculate the products: (4+3i)(7-3i)
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i=√-1
i^2=-1
i^3=-i
i^4=1
..
FOIL
(4+3i)(7-3i)
=28+21i-12i-9i^2
=28+9i+9
=37+9i