Question 962394

The measure of the three angles in a triangle must total of 180 degrees. The measure of angle A is 20 degrees less than the measure of angle C. The measure of angle C is twice the measure of angle B. Find the measure of each angle.


Thank you for your help. It helps me a lot to solve this problem.
<pre>Let measure of &#8736B be B
Then measure of &#8736C is: 2B
Measure of &#8736A is: 2B - 20
Therefore, we get: B + 2B + 2B - 20 = 180
5B = 200
&#8736B measures: {{{200/5}}}, or {{{highlight_green(40^o)}}}
&#8736C measures: {{{2(40)}}}, or {{{highlight_green(80^o)}}}
&#8736A measures: {{{80 - 20}}}, or {{{highlight_green(60^o)}}}