Question 962358
"The length of a rectangular patio is 8 feet less than twice it's width. The area of the patio is 280 square feet. Find the dimensions of the patio."
 I know for this problem that:
 length =2w-8
 width =w
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Equation:
length*width = Area
(2w-8)w = 280
2w^2-8w-280 = 0
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w^2 -4w - 140 = 0
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(w-14)(w+10) = 0
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Positive solution::
width = 14 ft
length = 2w-8 = 28-8 = 20 ft
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Cheers,
Stan H.
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