Question 962291
2cosx^2+3cos=2
2cosx^2 + 3cos - 2 = 0
(2cos - 1)*(cos + 2) = 0
cos(x) = -2  --> no real number solution.
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cos(x) = 1/2
x = pi/3 + 2n*pi, n = 0,1,2,3...
x = 5pi/3 + 2n*pi, n = 0,1,2,3...