Question 962272
{{{A*B=36}}}
{{{A=1+2B}}}
Substituting,
{{{(1+2B)B=36}}}
{{{2B^2+B-36=0}}}
{{{(B-4)(2B+9)=0}}}
Two solutions:
{{{B-4=0}}}
{{{B=4}}}
Then,
{{{A*4=36}}}
{{{A=9}}}
and
{{{2B+9=0}}}
{{{2B=-9}}}
{{{B=-9/2}}}
Then,
{{{A(-9/2)=36}}}
{{{A=-8}}}