Question 962216
Growth Model, {{{y=I*e^(-kt)}}}


{{{ln(y)=ln(I)-kt}}}
{{{ln(y)-ln(I)=-kt}}}
{{{kt=ln(I)-ln(y)}}}
{{{k=ln(I/y)/t}}}
{{{k=ln(1/0.5)/5700}}}
{{{k=ln(2)/5700}}}
{{{k=0.0001216}}}
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Specific Growth Model for Carbon-14, {{{highlight_green(y=Ie^(-0.0001216t))}}}.


How old is the bowl?
{{{kt=ln(I)-ln(y)}}}
{{{t=ln(I/y)/k}}}
Now, I=1,y=0.15.
Evaluate t.
{{{t=ln(1/0.15)/0.0001216}}}
{{{highlight(t=15600)}}}, years.