Question 961967
On a 4 sided pyramid you have a base and four triangles. First the area of the base,which is the area of the square, b^2:
A(b)= 4^4= 16 This is the area of the base.
The area of the pyramid is:
{{{Area= b^2+4((bh)/2)}}}
{{{Area= 16+4((4(5))/2)}}}
{{{Area= 16+40= 56}}}