Question 961920
Let the cost of one burger be x.
Let the cost of one order of fries be y.
Let the cost of one drink be z.
x+y+z=5...........equation 1
3x+2y+2z=12.50....equation 2
2x+4y+3z=14.......equation 3
Multiplying equation 1 by 2 we get
2x+2y+2z=10.......equation 4
Subtracting equation 4 from equation 2 we get,
3x+2y+2z-2x-2y-2z=12.5-10
x=2.5
The cost of one burger is $2.50.