Question 961732
{{{i^(2i) =0.0432139183}}}

since {{{i^(2i) =( i^2)^i}}}, and
{{{(i^2)^i =( -1)^i}}} which is equal to

{{{( -1)^i=0.043213918263772249774417737171728011275728109810633082980719}}} or, rounded {{{0.0432139183}}} which is a {{{rational}}}  number because it could be written in a form {{{p/q}}} as {{{432139183/10000000000}}}

so, {{{i^(2i) =0.0432139183}}} is a {{{rational}}}  number