Question 961695
{{{5y = -2x+4}}}
{{{y=-(2/5)x+4/5}}}
Perpendicular lines have slopes that are negative reciprocals,
{{{m[p](-(2/5))=-1}}}
{{{m[p]=5/2}}}
Use the point slope form and convert to slope-intercept form,
{{{y-16=(5/2)(x-6)}}}
{{{y-16=(5/2)x-15}}}
{{{highlight(y=(5/2)x+1)}}}
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