Question 961614
Should be simple, if you recognize the factorability.



{{{x^3-x^2-30x=0}}}
{{{x(x^2-x-30)=0}}}
still more factoring,...
{{{x(x-6)(x+5)=0}}}


Continue using Zero Product Rule.  Three solutions as a union.


x can be any one of  {-5, 0, 6}.