Question 961563
The problem is the area of a rectangle is given by a polynomial function A(x)=a^2b^2-ab-6. If the length of the rectangle is (ab-3), what would my width be? Show me step by step please.
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(ab)^2 -ab - 6 = (ab-3)(ab+2)
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Width = ab+2
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Cheers,
Stan H.
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