Question 82008
A^2+(3A-9)^2=(2A+1)^2
A^2+9A^2-54A+81=4A^2+4A+1
10A^2-4A^2-54A-4A+81-1=0
6A^2-58A+80=0 HERE YOU HAVE TO FIND FACTORS OF 6 & 80 WHEN MULTIPLIED & THEN ADDED WILL EQUAL -58.
IF YOU CAN'T DO THAT THEN USE THE QUADRATIC EQUATION (aX^2+bX+c=0: 
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
(2A-16)(3A-5)=0
2A-16=0
2A=16
A=16/2
A=8 ANSWER.
3A-5=0
3X=5
A=5/3
A=1 2/3 ANSWER.