Question 961513
Let {{{ n }}} and {{{ n+2 }}} = their ages
which are consecutive odd integers
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{{{ n*( n+2 ) = 575 }}}
{{{ n^2 + 2n = 575 }}}
Complete the square
{{{ n^2 + 2n + (2/2)^2 = 575 + (2/2)^2 }}}
{{{ n^2 + 2n + 1 = 576 }}}
{{{ ( n + 1 )^2 = 24^2 }}}
{{{ n + 1 = 24 }}}
{{{ n = 23 }}}
{{{ n+2  = 25 }}}
Their ages are 23 and 25
check:
{{{ 23*25 = 575 }}}
{{{ 575 = 575 }}}