<PRE><B>Question 961264</B>
Explain why 2^x = 15 cannot always be solved in the same way as 2^x = 16. How would you solve each?
------
16 is a power of 2,
So 2^x = 2^4
x = 4
-----------------
15 is hard to evaluate as a power of 2
so 2^x = 15
x*log(2) = log(15)
x = log(15)/log(2)
x = 3.0746
-----
Cheers,
Stan H.
---------------------</PRE>