Question 961085
cosx+sinx=1+sin2x
cosx+sinx=1+2sinxcosx
cosx+sinx=sinx^2+cosx^2+2sinxcosx (since sinx^2+cosx^2=1)
cosx+sinx=(sinx+cosx)^2
Solving we get,
sinx+cosx=1
x=0 degrees or x=90 degrees