Question 960465
{{{S[infinity]}}}{{{""=""}}}{{{a[1]/(1-r)}}}{{{""=""}}}{{{(1/2)/(1-1/6)}}}{{{""=""}}}{{{(1/2)/(6/6-1/6))}}}{{{""=""}}}{{{(1/2)/(5/6)}}}{{{""=""}}}{{{(1/2)*(6/5)}}}{{{""=""}}}{{{(1/cross(2))*(""^3cross(6)/5)}}}{{{""=""}}}{{{3/5}}}