Question 960663
a circle has an equation of 2(x-2)^2+2y^2=2. Find the center (h,k) and radius r and graph the circle. Find the intercepts if any,of the graph.
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2(x-2)^2+2y^2=2
(x-2)^2+y^2=1
center:(2,0)
radius=1
x-intercepts
set y=0
(x-2)^2=1
x-2=±√1=±1
x=2±1
x=3, 1
y-intercepts: none
                     
see graph below:
y=(1-(x-2)^2)^.5
{{{ graph( 300,300, -5, 5, -5, 5,(1-(x-2)^2)^.5,-(1-(x-2)^2)^.5) }}}