Question 960822

{{{sin(pi-x) = cos(x) sin(pi)-cos(pi) sin(x)}}}..... {{{sin(pi)=0}}} and {{{cos(pi)=-1}}}

{{{sin(pi-x) = cos(x)*0-(-1) sin(x)}}}

{{{sin(pi-x) = 0+ sin(x)}}}

{{{sin(pi-x)=sin(x)}}}