Question 960731
Rewrite the equation {{{ sin2x=cos(x) }}}
using only cos(x) (and numbers).
2sin*cos = cos
{{{2*sqrt(1-cos^2(x))*cos(x) = cos(x)}}}
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Then find all solutions to the equation.
2sin*cos = cos
2sin*cos - cos = 0
cos(2sin - 1) = 0
cos = 0
x = pi + n*pi n = 0,1,2,3...
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2sin - 1 = 0
sin(x) = 1/2
x = pi/6 + 2n*pi n = 0,1,2,3...
x = 5pi/6 + 2n*pi n = 0,1,2,3...