Question 960704
your problem is:


loga(m) - loga(n) + 2*loga(k)


since 2*loga(k) is equal to loga(k^2), then your problem can be restated as:


loga(m) - loga(n) + loga(k^2)


since loga(m) - loga(n) is equal to loga(m/n), then your problem can be restated as:


loga(m/n) + loga(k^2)


since loga(m/n) + loga(k^2) is equal to loga(m/n * k^2), then your problem can be restated as:


loga(m/n * k^2)